Question

A particle starts from the point $(0m,8m)$ and moves with uniform velocity of $3\hat{i}$m/s. After $5$ seconds, the angular velocity of the particle about the origin will be

• A. $\frac{8}{289}rad/s$
• B. $\frac{3}{8}rad/s$
• C. $\frac{24}{289}rad/s$
• D. $\frac{8}{17}rad/s$

Answer 1

The correct option is C $\frac{24}{289}rad/s$

$m{v}_1{r}_1=m{v}_2{r}_2$

$v_1=3m/s,r_1=8m,r2=\sqrt{8^2+{15}^2}=17m$

$v_2=3\ast 8/17$

$\omega =v_2/r_2=(3\ast 8)/(17\ast 17)=24/289rad/sec$

Option C is correct.