CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle starts to move in a straight line from a point with velocity 10ms1 and acceleration 2.0ms2. Find position and velocity of the particle at t = 10 s

A
S = 0 m, v = 10 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
S = 0 m, v = -10 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
S = 50 m, v = 10 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
S = 0 m, v = 0 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B S = 0 m, v = -10 m/s
Displacement at t = 10 s is
s=ut+12at2
=10×10+12×(2.0)×(10)2
=100100=0(zero)
i.e., after 10 s, the particle will come back to the starting point.
Velocity at t = 10 s is
v=u+at
v=10+(2)10
=10ms1.

i.e., velocity is 10ms1 opposite to the direction of initial starting velocity.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon