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Question

A particle travels 10m in first 5 seconds 10 cm in next 3 seconds. Assuming constant acceleration what is the distance travelled in next 2 second ?

A
8.3 m
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B
9.3 m
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C
10.3 m
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D
None of these
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Solution

The correct option is A 8.3 m

Let assume initial velocity is u and constant acceleration a. using s=ut + (0.5)at2,

for first 5 second

10 = 5u + (0.5)a(25)

for next 3 seconds, t=8 and s=20

20=8u+(0.5)a(64)

Solving,

a=13 and u=76

Now for next 2 seconds, t=10 and S:

S=(10)76+(0.5)13(100)

S = 1706

Now distance travelled in 2 sec = 170620=506 meter


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