A particle travels 10m in first 5 seconds 10 cm in next 3 seconds. Assuming constant acceleration what is the distance travelled in next 2 second ?
Let assume initial velocity is u and constant acceleration a. using s=ut + (0.5)at2,
for first 5 second
10 = 5u + (0.5)a(25)
for next 3 seconds, t=8 and s=20
20=8u+(0.5)a(64)
Solving,
a=13 and u=76
Now for next 2 seconds, t=10 and S′:
S′=(10)76+(0.5)13(100)
S′ = 1706
Now distance travelled in 2 sec = 1706−20=506 meter