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Question

A particle when thrown. moves such that it passes from same height at $$2$$ and $$10 s$$, the height is:


A
g
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B
2g
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C
5g
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D
10g
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Solution

The correct option is D $$10g$$

If t1 and t2 are the time when the body is at the same height Then  $$h = \dfrac{1}{2} \times  g\times {t}_1\times  {t}_2$$ $$h = \dfrac{1}{2} \times  g\times {2}\times  {10}$$h = 10 g 

So that the correct option is D







Physics

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