A party of 9 persons are to travel in two vehicles, one of which will not hold more than 7 and other not more than 4. The number of ways the party can travel is
A
120
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B
220
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C
236
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D
246
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Solution
The correct option is D246 Vehicle 1 and Vehicle 2 can hold (7,2),(6,3)(5,4) persons respectively.
So, required number of ways =9C72C2+9C63C3+9C54C4=246