Question

# A patient in a hospital is given soup daily in a cylindrical bowl of diameter $7cm$. If the bowl is filled with soup to a height of $4cm$, how much soup the hospital have to prepare daily to serve $250$ patients.

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Solution

## Radius of the cylindrical bowl $=\frac{7}{2}cm$, Height of the cylindrical bowl $=4cm$Volume of the cylindrical bowl $={\mathrm{\pi r}}^{2}\mathrm{h}$ $=\frac{22}{7}×{\left(\frac{7}{2}\right)}^{2}×4$ $=\frac{22}{7}×\frac{7}{2}×\frac{7}{2}×4$ $=22×7=154c{m}^{3}$Volume of the soup given to $250$ patients $=250×154$ $=38,500c{m}^{3}$ $=\frac{38500}{1000}=\frac{385}{10}=38.5litres$ Note -: $1litre=1000c{m}^{3}$Therefore, volume of the soup given to $250$ patients $=38.5litres$

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