Question

A pen stand made of wood is in the shape of a cuboid with four conical depressions and a cubical depression to hold the pens and pins, respectively. The dimension of the cuboid are $10cm$, $5cm$ and $4cm$. The radius of each of the conical depressions is $0.5cm$ and the depth is $2.1cm$. The edge of the cubical depression is $3cm$. The volume of the wood in the entire stand is:
(Insert answer in the nearest integer)

Answer 1

Volume of cone $=\frac{1}{3}\pi \times (0.5{)}^2\times (2.1)=0.55c{m}^3$

So, volume of 4 cones$=4\left(0.55\right)=2.2c{m}^3$

Volume of cube$=(edge{)}^3=3^3=27c{m}^3$

Volume of cubiod $=lbh=10\times 5\times 4=200c{m}^3$

Volume of wood $=200-(2.2+27)=170.8c{m}^3$