A pendulum bob of mass m=80mg, carrying a charge of q=2×10−8C, is at rest a horizontal uniform electric field of E=20,000V/m. The tension T in the thread of the pendulum and the angle α it makes with vertical is (take g=9.8m/s2)
A
α≈27o
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B
T≈880μN
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C
T=8.8μN
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D
α≈356o
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Solution
The correct options are Aα≈27o BT≈880μN Force =qE=(2×10−8×20000)N=4×10−4N