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Question

A pendulum bob of mass m=80mg, carrying a charge of q=2×108C, is at rest a horizontal uniform electric field of E=20,000V/m. The tension T in the thread of the pendulum and the angle α it makes with vertical is (take g=9.8m/s2)

A
α27o
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B
T880μN
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C
T=8.8μN
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D
α356o
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Solution

The correct options are
A α27o
B T880μN
Force =qE=(2×108×20000)N=4×104N
Tcosθ=mg -----------(I)
Tsinθ=4×104 -------------(II)
So, tanθ=4×10480×106×9.8=408×9.812
So, θ=27
T=mgcosθ=80×106×9.80.89=880μN

1107412_1017197_ans_c226ff44ba594eb3825a4e48147335b3.png

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