A pendulum suspended from the ceiling of a train has a time period T when the train is at rest. When the train is accelerating with a uniform acceleration, the time period will

increase

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decrease

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become infinite

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remain unaffected

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Solution

The correct option is B decrease
Time period $T_{1}$ when the train is a rest
$T_{1} = 2 π \sqrt{\frac{l}{g}}$
Now let the train be accelerating with an acceleration $a$
$T_{2} = 2 π \sqrt{\frac{l}{a^{2} + g^{2}}}$
It is clearly seen that $T_{2} < T_{1}$
Hence the time period has decreased

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A pendulum suspended from the ceiling of a train has a time period T when the train is at rest. When the train is accelerating with a uniform acceleration, the time period will

The correct option is B decreaseTime period T1 when the train is a restT1=2π√lgNow let the train be accelerating with an acceleration aT2=2π√la2+g2It is clearly seen that T2<T1Hence the time period has decreased

The correct option is B decrease
Time period $T_{1}$ when the train is a rest
$T_{1} = 2 π \sqrt{\frac{l}{g}}$
Now let the train be accelerating with an acceleration $a$
$T_{2} = 2 π \sqrt{\frac{l}{a^{2} + g^{2}}}$
It is clearly seen that $T_{2} < T_{1}$
Hence the time period has decreased