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Standard X

Physics

Theoretical Verification of Law of Conservation

A person brin...

Question

A person brings a mass of 2 kg from A to B. The increase in kinetic energy of the mass is 4 J and the work done by the person on the mass is -10 J. The gravitational potential difference between B and A is (i.e., $V_{B} - V_{A}$ )

4 J/kg

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7 J/kg

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- 3J/kg

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- 7J/kg

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Solution

The correct option is D
- 7J/kg

$W_{A - B} = (U_{B} - U_{A}) + (K_{B} - K_{A})$

or $W_{A \to B} = m (V_{B} - V_{A}) + (K_{B} - K_{A})$

Substituting the value we get;

-10 = 2 $(V_{B} - V_{A}) + 4$

or $V_{B} - V_{A} = - 7 J / K g$

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A person brings a mass of 2 kg from A to B. The increase in kinetic energy of the mass is 4 J and the work done by the person on the mass is -10 J. The gravitational potential difference between B and A is (i.e., VB−VA)

The correct option is D - 7J/kg WA−B=(UB−UA)+(KB−KA) or WA→B=m(VB−VA)+(KB−KA) Substituting the value we get; -10 = 2(VB−VA)+4 or VB−VA=−7J/Kg

A person brings a mass of 2 kg from A to B. The increase in kinetic energy of the mass is 4 J and the work done by the person on the mass is -10 J. The gravitational potential difference between B and A is (i.e., $V_{B} - V_{A}$ )

The correct option is D
- 7J/kg

$W_{A - B} = (U_{B} - U_{A}) + (K_{B} - K_{A})$

or $W_{A \to B} = m (V_{B} - V_{A}) + (K_{B} - K_{A})$

Substituting the value we get;

-10 = 2 $(V_{B} - V_{A}) + 4$

or $V_{B} - V_{A} = - 7 J / K g$