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Question

A person is standing on a truck moving with a constant velocity of 14.7 m/s on a horizontal road. The man throws a ball v that it returns to the truck after the truck has moved 58.8 m. Find the speed and the angle of projection (a) as seen from the truck, (b) as seen from the road.


A
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B
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C
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D
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Solution

The correct option is A

Truck is velocity = 14.7 ms

Man catches the ball after distance = 58.8 m

Time taken = 58.814.7 = 4 sec

Ball should be in air for 4 sec only

T = 4 sec

vy = u

ay = 10

t = 4

4 = 2u10

u = 20 ms

So the ball was thrown with 20 ms in perpendicular direction.

If I see from the road the ball will seem to have two velocity.

One in vertical direction 20 ms and one in horizontal direction = velocity of truck = 14.7 ms

Velocity = (20)2 + (14.7)2 = 24.8

Angle = tan1(2014.7) = tan1(1.36)


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