Question

A person measures the time period of a simple pendulum inside a stationary lift and finds it to be T . If the lift starts accelerating upwards with an acceleration g/3, the time period of pendulum will become

• A. $\sqrt{3}T$
• B. $\left(\sqrt{3}/2\right)T$
• C. $T/\sqrt{3}$
• D. T/3

Answer 1

The correct option is B

$\left(\sqrt{3}/2\right)T$

$T=2\pi \sqrt{\frac{2}{g+\frac{g}{3}}}=2\pi \sqrt{\frac{3}{4}\frac{2}{g}}=\frac{\sqrt{3}}{2}T$