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Question

A person observes two trains one of them is coming towards with speed of 4 m/sec and another is going away with same speed. If the two trains blowing a whistle with frequency 240 Hz. The beat frequency heard by stationary person will be (speed of sound in air =320 m/sec.)


A
zero
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B
3
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C
6
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D
12
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Solution

The correct option is B 6
Let vs1 and vs2 be the velocities of the two sources then the frequencies heard by the observer from each of the source is given by
n1=n(vvvs1)=240(320316)=243 Hz 
n2=n(vv+vs2)=240(320324)=237 Hz
beats=n1n2=(243237) Hz=6 Hz
 

Physics

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