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Question

A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2and then down with an acceleration of, is

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Solution

When the lift moves up with an acceleration of 2 ms-2 ,the apparent weight of the person is,F' = mg+a or F' =609.8+2 or F' =60×11.8 or F' = 708 N.where m = 60 kg, g = 9.8 ms-2, a = 2 ms-2When the lift moves down , the apparent weight of the person is given by,F' = mg-a or F' = 609.8-2 or F' = 60×7.8 or F'=468 N.

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