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Question

A person of mass 60kg is inside a lift of mass 940kg and present the button of control panel. The lift starts moving upwards with an acceleration 1.0m/s2 . If g=10ms2 , the tension in the supporting cable is -

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Solution

The tension in the string is given as follows

T=m(g+a)

By substituting the values of mass and acceleration given in the question we get

T=1000×(10+1)

=11000N

Hence, the tension in the string is11000N


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