Question

A person on a morning walk completes one round around a circular park of diameter $500m$, in $1$ minute. What will be the distance covered and the displacement at the end of $5$ minutes $30$ s?

Answer 1

$d=500m$

$\left(2\pi r\right)$

circumference $=2\pi \left(\frac{500}{2}\right)$

speed $=500\pi \frac{m}{min}$

distance $=500\pi \frac{m}{min}\times 5.5min$

$=2750\pi m$

$=8635m$

Displacement

$500\pi$ is one round

$2750\pi$ is $\to ?$

$\frac{2750\pi }{500\pi }=5.5rounds$

displacement $=$ length of diameter

$=500m$.