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Question

A person on tour has 4200 for his expenses. If he extends his tour for 3 days, he has to cut down daily expenses by 70. Find the original duration of the tour.


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Solution

Step:Find the original duration of the tour.

Given, Total money a person has=4200

Let x days be the duration of the tour.

Expense in a day =4200x

Duration of the extended tour =3days

Then, Expense in a day =4200x+3

As per the question, we get

4200x-4200x+3=70

42001x-1x+3=70

1x-1x+3=704200

1x-1x+3=160

x+3-xxx+3=160

3x2+3x=160

x2+3x=180

x2+3x-180=0

x2+15x12x180=0

x(x+15)12(x+15)=0

(x+15)(x12)=0

x+15=0orx12=0

x=-15orx=12

Since x cannot be a negative So, x=12

Hence, the original duration of the tour is 12 days.


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