A person throws balls into air after every second. The next ball is thrown when the velocity of the first ball is zero. How high do the ball rise above his hand?
The correct option is C5m According to question, second ball is thrown 1s after the first ball and at this instance first ball is at its maximum height. This is because at maximum height, velocity of the ball is 0. ⇒ Time taken by the ball to reach maximum height is 1s. ⇒ Height =12gt2=5m