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Question

A person walks at a velocity v in a straight line forming an angle α with the plane of a plane mirror. the velocity at which he approaches his image is:
1123715_1b949dbe371a4236ba864dc00be954b8.png

A
v
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B
vsinα
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C
2vsinα
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D
2vcosα
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Solution

The correct option is D 2vcosα
  • Since it is a plane mirror vertical component of velocity have no significance.
  • The person approaches the mirror with a horizontal speed of vcosα.
  • Hence his image also move towards the mirror with same velocity vcosα in the opposite direction.
  • Velocity at which he approaches his image is ,v=vcosα(vcosα)=2vcosα

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