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Question

A person walks at a velocity V in a straight line forming an angle θ with the plane of a plane mirror. Find the velocity Vrel with which he approaches his image?
126759_b1de7c0f071940699e665777bd6a7909.png

A
2Vsinθ
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B
2V
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C
2Vcosθ
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D
V2sinθ
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Solution

The correct option is A 2Vsinθ
If V be the velocity of approach at an angle θ, then velocity along the perpendicular direction will be Vsinθ
The image will also approach at the same speed, hence the relative speed of approach will be 2Vsinθ
120768_126759_ans_282ac6c4afa547ee954244f0cacc3abe.png

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