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Question

A photon and electron both have same energy E0=100 eV, then


A
both have same wavelength
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B
photon has longer wavelength
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C
electron has longer wavelength
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D
electron has lesser momentum
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Solution

The correct option is B photon has longer wavelength
Wave length of the electronλe  = h2mE0Wavelength of the photonλp  = hcE0where h is the Planck's constantλp λe = hcE0×2mE0h       =cE0×2mE0       =2mc2E0       =2×9.1×1031×9×1016100×1.6×1019        < 1λp  > λe i.e the photon has longer wavelength and lesser momentum( because p=hλ).

Physics

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