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Question

A photosensitive metallic surface has work function, h 0. If photons of energy 2h 0 fall on this surface, the electrons come out with a maximum velocity of 4 106 m/s. When the photon energy is increased to 5h0, then maximum velocity of photo electrons will be

A
2 107 m/s
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B
2 106 m/s
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C
8 105 m/s
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D
8 106 m/s
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Solution

The correct option is D 8 106 m/s
2hv0=hv0+12m(4×106)2
5hv0=hv0+12mv24×12m(4×106)
=12mv2v=8×106m/s

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