Question

A picnic spot is 55 yards away from a school. The school bus stops at 22 yards away from the school. What percentage of distance remains to reach the picnic spot?

• A. 40%
• B. 80%
• C. 20%
• D. 60%

Answer 1

The correct option is D 60%

Distance of the picnic spot from the school = 55 yards
Distance that the school bus stops at = 22 yards

Remaining distance = 55 - 22 = 33 yards

Therefore, percentage of distance remaining = $\frac{33}{55}\times 100=60\%$