A piece of equipment cost a certain factory Rs 600,000. If it depreciates in value, 15% the first, 13.5% the next year, 12% the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?

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Solution

Cost of the piece of equipment at the end of the first year = Rs 600000 – 15% of 600000
= Rs 600000 – Rs 90000
= Rs 510000
Cost of the piece of equipment at the end of the second year = Rs 600000 – 13.5% of 600000
= Rs 600000 – Rs 81000
= Rs 519000
Cost of the piece of equipment at the end of the third year = Rs 600000 – 12% of Rs 600000
= Rs 600000 – Rs 72000
= Rs 528000
The numbers 510000, 519000, 528000 are in an A.P. whose first term in 510000 and common difference is 9000.
∴ Cost of the piece of equipment at the end of 10 years = a + (10 – 1)d
= 510000 + 81000
= Rs 591000

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A piece of equipment cost a certain factory $R s . 6, 00, 000$ . If it depreciates in value, $15 %$ the first, $13.5 %$ the next year, $12 %$ the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?

Q. A piece of equipment costs a certain factory

R s . 600, 000.

If it in value,

15 %

the first,

13.5 %

the next year,

12 %

the third year and so on. What will be it's a value at the end of

10

years, all percentages applying to the original cost

In a factory, the cost of a machine is ₹ 6,00,000. If its value depreciates 15% the first year, 13.5 % the next year, 12% the third year, and so on. Calculate its value at the end of 10 years, applying all percentages to the original cost?

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