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Question

A piece of solid weights $$120g$$ in air, $$80g$$ in water and $$60g$$ in a liquid. The relative density of the solid and that of the liquid are respectively


A
3,2
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B
2,34
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C
32,2
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D
2,32
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Solution

The correct option is C $$\cfrac{3}{2},2$$
Relative density of solid$$=\cfrac { W\left( Air \right) -W\left( liquid \right)  }{ W\left( Air \right) -W\left( Water \right)  } =\cfrac { 120-60 }{ 120-80 } =\cfrac { 3 }{ 2 } $$
Relative density of liquid$$=\cfrac { 120-0 }{ 120-60 } =\cfrac { 120 }{ 60 } =2$$

Physics

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