Question

# A piece of solid weights $$120g$$ in air, $$80g$$ in water and $$60g$$ in a liquid. The relative density of the solid and that of the liquid are respectively

A
3,2
B
2,34
C
32,2
D
2,32

Solution

## The correct option is C $$\cfrac{3}{2},2$$Relative density of solid$$=\cfrac { W\left( Air \right) -W\left( liquid \right) }{ W\left( Air \right) -W\left( Water \right) } =\cfrac { 120-60 }{ 120-80 } =\cfrac { 3 }{ 2 }$$Relative density of liquid$$=\cfrac { 120-0 }{ 120-60 } =\cfrac { 120 }{ 60 } =2$$Physics

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