Question

# A piggy bank contains a hundred $50p$ coins, fifty $Rs1$coins, twenty $Rs2$ coins, and ten $Rs5$ coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin will not be a $Rs5$coin?

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Solution

## Given ,Number of $50p$coins $=100$Number of $Rs1$coins $=50$Number of $Rs2$coins $=20$Number of $Rs5$ coins $=10$Total number of coins $=100+50+20+10$ $=180$We know that,$\therefore$ the probability that the coin will be a $Rs5$ $=\frac{10}{180}$ $=\frac{1}{18}\phantom{\rule{0ex}{0ex}}=0.055$Now,the probability that the coin will not $Rs5=1-$the probability that will be a $Rs5$ $=1-0.055\phantom{\rule{0ex}{0ex}}=0.945$Hence, the required solution is $0.945$ .

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