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Question

A pipe can empty the tank in  $$8$$ hours and another  can fill  $$6$$  liters in $$ 1$$  min. If both pipe opened , the tank is emptied in  $$12$$ hours . The capacity of tank is ?


Solution

Let capacity of the Tank is 100 %
First pipe can empty the tank  = 8 hours = 8 *60 = 480 min
Work rate of the pipe  = x/480 liter per min.
The work rate of both pipe = x/(12 *60) liter per min = (x / 480) - (x / 720) = Work rate of second pipe
720 x - 480x = 6 liter *720 *480
240x = 6 *720 *480
x= 8640 litres.

Mathematics

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