A plane electromagnetic wave has a maximum electric field magnitude of 3-20-10-4V-m- Find the magnetic field amplitude-

The amplitude of the magnetic field in the wave is, B_m=E_m/c=3.20×10^ 4V/m/2.998×10^8m/s=1.07×10^ 12T . ...

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Standard XII

Physics

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A plane elect...

Question

A plane electromagnetic wave has a maximum electric field magnitude of $3.20 \times 10^{- 4} V / m$ . Find the magnetic field amplitude.

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Solution

The amplitude of the magnetic field in the wave is,
$B_{m} = \frac{E_{m}}{c} = \frac{3.20 \times 10^{- 4} V / m}{2.998 \times 10^{8} m / s} = 1.07 \times 10^{- 12} T$ .

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A plane electromagnetic wave has a maximum electric field magnitude of 3.20×10−4V/m. Find the magnetic field amplitude.

The amplitude of the magnetic field in the wave is,Bm=Emc=3.20×10−4V/m2.998×108m/s=1.07×10−12T.

A plane electromagnetic wave has a maximum electric field magnitude of $3.20 \times 10^{- 4} V / m$ . Find the magnetic field amplitude.

The amplitude of the magnetic field in the wave is,
$B_{m} = \frac{E_{m}}{c} = \frac{3.20 \times 10^{- 4} V / m}{2.998 \times 10^{8} m / s} = 1.07 \times 10^{- 12} T$ .