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Question

A plane is flying 2400 km from source A to destination B. Speed of the plane is 600 km/hr and speed of the wind tailing it is 40 km/hr. How many hours after take off would it be faster to go to B than to return to A in case of an emergency
  1. 1.5 hours
  2. 1.75 hours
  3. 1.65 hours
  4. 2 hours


Solution

The correct option is D 2 hours

From A to B speed of flight = 640 km/hr , while for the reverse it is = 560 km/hr.

Since, ‘x’ is the distance from A, hence, as per the question:

x560(2400x)640

x1120  km.

  Minimum such distance  = 1120 km and time taken to cover 1120 km =1120560=2 hr.

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