A plane is revolving around the earth with a speed if $100 k m / h r$ at a constant height from the surface of earth. The change in the velocity as it travels half circle is

200 k m / h r

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150 k m / h r

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100 \sqrt{2} k m / h r

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Solution

The correct option is C $200 k m / h r$
As we know,
$Δ v = 2 v sin (\frac{θ}{2}) = 2 \times v \times sin 90^{o}$
$= 2 \times 100 = 200 k m / h r$

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A plane is revolving around the earth with a speed if 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is

The correct option is C 200 km/hrAs we know,Δv=2vsin(θ2)=2×v×sin90o=2×100=200 km/hr

A plane is revolving around the earth with a speed if $100 k m / h r$ at a constant height from the surface of earth. The change in the velocity as it travels half circle is

The correct option is C $200 k m / h r$
As we know,
$Δ v = 2 v sin (\frac{θ}{2}) = 2 \times v \times sin 90^{o}$
$= 2 \times 100 = 200 k m / h r$