A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is

200 km/hr

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150 km/hr

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$100 \sqrt{2} k m / h r$

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Solution

The correct option is A
200 km/hr

$Δ v = 2 v s i n (\frac{θ}{2}) = 2 \times v \times s i n 90^{\circ} = 2 \times 100 = 200 k m / h r$

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A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is

The correct option is A 200 km/hr Δv=2vsin(θ2)=2×v×sin90∘=2×100=200km/hr

The correct option is A
200 km/hr

$Δ v = 2 v s i n (\frac{θ}{2}) = 2 \times v \times s i n 90^{\circ} = 2 \times 100 = 200 k m / h r$