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Question

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms1, the escape velocity (in km s1) from the surface of the planet would be

A
110
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B
110.0
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C
110.00
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Solution

Mass of planet, MP=10Me, where Me is mass of earth.
Radius of planet, RP=Re10, Where Re is radius of earth.
Escape speed is given by, vP=2GMR

For planet, vP=2G×MPRP

vP=10×ve
vP=10×11=110 km s1

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