A player caught a cricket ball of mass $150 g$ moving at a rate of $20 - m / s$ . The catching process is completed in $0.1$ second. What is the force exerted by the ball on the hand of the player?

15 N

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20 N

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30 N

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40 N

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Solution

The correct option is C $30 N$
$M = 150 g$
$v = 20 m / s$
$t = 0.1 s$
$a = (v - u) / t$
$= (20) / 0.1$
$= 200 m$
$f = m a$
$= 150 \times 200$
$= 30000 / 1000$
$= 30 N$
Hence,
option $(C)$ is correct answer.

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A player caught a cricket ball of mass 150 g moving at a rate of 20−m/s. The catching process is completed in 0.1 second. What is the force exerted by the ball on the hand of the player?

The correct option is C 30 NM=150gv=20m/st=0.1sa=(v−u)/t=(20)/0.1=200mf=ma=150×200=30000/1000=30NHence,option (C) is correct answer.

A player caught a cricket ball of mass $150 g$ moving at a rate of $20 - m / s$ . The catching process is completed in $0.1$ second. What is the force exerted by the ball on the hand of the player?

The correct option is C $30 N$
$M = 150 g$
$v = 20 m / s$
$t = 0.1 s$
$a = (v - u) / t$
$= (20) / 0.1$
$= 200 m$
$f = m a$
$= 150 \times 200$
$= 30000 / 1000$
$= 30 N$
Hence,
option $(C)$ is correct answer.