Question

# A point charge q is kept at a distance of 2R from centre of an uncharged spherical shell of radius R. The potential at centre of the shell due to charges induced on shell is

A
q4πE0R
B
q4πE02R
C
q4πE0R
D
Zero

Solution

## The correct option is C $$\dfrac{-q}{4 \pi E_0R}$$Charge $$=q$$distance $$=2R$$radius $$=R$$$$V=$$ Potential at centre of the shell due to charge induced on shell.As the electric field inside a conductor is zero. The electrostatic potential is constant it. The potential at centre will be the potential of entire conductor. The entire charge of conductor is on surface $$N$$.Now, $$V=\dfrac { -1 }{ 4\pi { \epsilon }_{ 0 } } \dfrac { q }{ R }$$The $$(-Ve)$$ sign due to spherical shell of centre (inside).PhysicsNCERTStandard XII

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