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Standard XII

Physics

Potential Energy - External Viewpoint

A point charg...

Question

A point charge Q is placed at A at a distance $\frac{R}{2}$ from center of a thick conducting shell of inner radius R and outer radius 2R as shown in figure. Point P is at distance $\frac{3 R}{2}$ from centre. Field at P due to induced charges on shell is $\frac{n K Q}{R^{2}}$ , then n is

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Solution

Field at P is zero
So $E_{A} = E_{I}$
$\frac{K Q}{R^{2}} = E_{I}$ (Field due to induced charges)

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A point charge Q is placed at A at a distance R2 from center of a thick conducting shell of inner radius R and outer radius 2R as shown in figure. Point P is at distance 3R2 from centre. Field at P due to induced charges on shell is nKQR2, then n is

Field at P is zero So EA=EI KQR2=EI (Field due to induced charges)

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Field at P is zero
So $E_{A} = E_{I}$
$\frac{K Q}{R^{2}} = E_{I}$ (Field due to induced charges)