A point D is taken on the side of BC of - ABC such that BD -2 DC- ThenA- area ABD -2 area - ADC B- area - ABD - area - ADC C- area - ABD -1 - 2 area - ADC D- area - ABD - area - ADC

The correct option is A area (∆ABD) = 2area (∆ADC) ...

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Byju's Answer

Standard IX

Mathematics

Line from Vertex Divides the Length of Opposite Side and Area

A point D is ...

Question

A point D is taken on the side of BC of ∆ABC such that BD = 2DC. Then

area (∆ABD) = area (∆ADC)

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area (∆ABD) = ¹/₂ area (∆ADC)

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area (∆ABD) < area (∆ADC)

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area (∆ABD) = 2area (∆ADC)

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Solution

The correct option is D
area (∆ABD) = 2area (∆ADC)

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A point D is taken on the side of BC of ∆ABC such that BD = 2DC. Then

The correct option is D area (∆ABD) = 2area (∆ADC)

The correct option is D
area (∆ABD) = 2area (∆ADC)