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Question

A point mass starts moving in a straight line with constant acceleration "a". At a time t after the beginning of motion, the acceleration changes sign, without change in magnitude. Determine the time t0 from the beginning of the motion in which the point mass returns to the initial position.

A
(2+3)t
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B
(2+2)t
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C
(3+2)t
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D
(12+2)t
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Solution

The correct option is B (2+2)t
let s be the distance travled in time t
s=at22(1)
let t1 be the time in which it comes to its initial position
using equation of motions=ut+at22
now u=at,t=t1,s=s,a=a
s=(at)t1at212
s=att1+at212(2)
using (1)&(2)
t212tt1t2
solving t1=(2+1)t
t0=t1+t
t0=(2+2)t





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