Question

A point moves in the $x-y$ plane such that the sum of its distances from two mutually perpendicular lines is always equal to $3$, then find the area enclosed by the locus of the point.

Answer 1

Given $x+y=3$

i.e., Equation of a straight line.

$\therefore$ Required area $=4\times \frac{1}{2}\times 3\times 3$

$=18$ sq. units.