A point object is placed on the principal axis of a convex lens of focal length at a distance of to the left of it. The diameter of the lens is . An eye is placed to right of the lens and a distance below the principal axis. The maximum value of to see the image is____.
Step 1. Given data
We have to find the maximum value of distance .
Step 2. Formula used.
A lens is a piece of a refracting medium bounded by two surfaces, at least one of which is a curved surface.
We will calculate the image distance by using the lens formula.
This formula represents the relation between object distance , image distance , and focal length .
According to the sign of convention, object distance
Step 3. Calculate the image distance.
By using the lens formula, we get,
So, the image distance is , which means the image is formed at the center of curvature.
Draw the ray diagram
Step 4. Find the value of distance.
According to the above figure, and are in symmetric form.
The maximum value of to see the image is .