Question

# A point object O is placed in front of a transparent slab at a distance x from its closer surface. It is seen from the other side fo the slab by light incident nearly normally to the slab. The thickness of the slab is t and its refractive index is μ. Show that the apparent shift in the position fo the object is independent of x and find its value.

A
t(1+tμ),
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t(1tμ),
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
t(2tμ),
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
t(2+tμ),
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A t(1−tμ), The situation is shown in figure. Because of the refraction at the first surface, the image of O is formed at O1. For this refractiion, the real depth is AO = x and the apparent depth is AO1. Also the first medium is air and the second is the slab. Thus, xAO1=1μor,AO1=μx. The point O1 acts as the object for the refractiion at the second surface. Due to this refraction the image of O1 is formed at I. Thus, BO1BI=μ or, AB+AO1BI=μ or t+μxBI=μ or BI=x+tμ. The net shift in OI=OB−BI=(x+t)−(x+tμ) =t(1−tμ), which is independent of x.

Suggest Corrections
0
Related Videos
Playing with Glass Slabs
PHYSICS
Watch in App
Explore more