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Image of a Point with Respect to X = a

A point P(3, ...

Question

A point P(3, 4) is reflected in line x + 3 = 0. Then the image of P is

(-8, 4)

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(-9, 4)

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(-6, 4)

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(-5, 4)

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Solution

The correct option is B
(-9, 4)

Given line x + 3 = 0 $\Rightarrow$ x = -3

Let P' (x, 4) be the image of P(3, 4), Using midpoint formula

$\frac{x + 3}{2} = - 3 \Rightarrow x = - 9$

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Similar questions

Complete the following table :

Point Transformation Image

(a) (5, -7)-------------------------------(-5, 7)

(b) (4, 2) Reflection x-axis ---------

(d) (6, -6) ----------------- (-6, 6)

(e) (4, -8) ------------------ (-4, -8)

\frac{5}{11} x - x^{4}

[4 M a r k s]

L = 0

P = 0

B

A (2, 1, 6)

L = 0

P = 0

A^{'}

L = 0

\frac{x - 2}{3} = \frac{y - 1}{4} = \frac{z - 6}{5}

P = 0

x + y - 2 z = 3

L_{1} = 0

P (2, 3)

L

Q (4, 5)

R (0, 0)

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