A point P on X-axis is at distance 13 from A(11,12). Find the coordinates of P.

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Solution

A point on X axis can be represented as (a,0)
Square of Distance between (a,0) and (11,12) is
(a-11)^2 + (0-12)^2 = 13^2(given)
(a-11)^2 = 169-144 = 25 = 5^2
a-11 = 5
a = 16

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A point P on X-axis is at distance 13 from A(11,12). Find the coordinates of P.

A point on X axis can be represented as (a,0)Square of Distance between (a,0) and (11,12) is(a-11)^2 + (0-12)^2 = 13^2(given)(a-11)^2 = 169-144 = 25 = 5^2a-11 = 5a = 16

A point on X axis can be represented as (a,0)
Square of Distance between (a,0) and (11,12) is
(a-11)^2 + (0-12)^2 = 13^2(given)
(a-11)^2 = 169-144 = 25 = 5^2
a-11 = 5
a = 16