CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A point particle of mass m moves along the uniformly rough track PQR as shown in the figure. The coefficient of friction between the particle and the rough track equals μ. The particle is released from rest from the point P and it comes to rest at a point R. The energies lost by the ball over the parts PQ and QR of the track are equal to each other and no energy is lost when particle changes direction from PQ to QR. The distance x(=QR) is equal to

A
3.5 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6.5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4.5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3.5 m
Let Wf denote the work done due to friction and Wg denote the work done due to gravity
(Wf)PQ=(Wf)QR
μ mg l cos 30=μ mg×cos 0×x
here sin 30=2ll=4 m
μ mg×4×32=μ mgx
x=23 m=3.5 m


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Kinetic Energy and Work Energy Theorem
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon