A position dependent force $F = 7 - 2 x + 3 x^{2}$ acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is

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270

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135

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Solution

The correct option is D
135

$W = 5 \int 0 F d x = 5 \int 0 (7 - 2 x + 3 x^{2}) d x = [7 x - x^{2} + x^{3}]_{0}^{5}$

= 35 - 25 + 125 = 135

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A position dependent force F=7−2x+3x2 acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is

The correct option is D 135 W=5∫0Fdx=5∫0(7−2x+3x2)dx=[7x−x2+x3]50 = 35 - 25 + 125 = 135

A position dependent force $F = 7 - 2 x + 3 x^{2}$ acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is

The correct option is D
135

$W = 5 \int 0 F d x = 5 \int 0 (7 - 2 x + 3 x^{2}) d x = [7 x - x^{2} + x^{3}]_{0}^{5}$

= 35 - 25 + 125 = 135