A positive charge q is placed in front of a conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube to the charges appearing on its surface.

Open in App

Solution

Electric field at a point due to a given
charge, E = $\frac{q}{4 π \in_{0} d^{2}}$ ,
where q is the charge and R the distance between the point and the charge.

Suggest Corrections

Similar questions

A positive charge q is placed in front of a conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube due to the charges appearing on its surface.

Q. A positive charge

q

is placed in front of a conducting solid cube of side

a

at distance

d

from its center. Find the electric field at the center of the cube due to the charges appearing on its surface.

Q. A charge

Q

is placed at the centre of a cube. Find the flux of the electric field through three surfaces of the cube.

Q. Assertion :A point charge

q

is placed in front of a solid conducting sphere. Electric field due to induced charges at the centre of sphere is zero. Reason: Electric field at point inside the solid body of conductor is zero.

Q. The electric field at a distance 2 cm from the centre of a hollow spherical conducting shell of radius 4 cm having a charge of

2 \times 10^{- 3}

C on its surface is :

Join BYJU'S Learning Program

A positive charge q is placed in front of a conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube to the charges appearing on its surface.

Electric field at a point due to a givencharge, E = q4π∈0d2,where q is the charge and R the distance between the point and the charge.

Electric field at a point due to a given
charge, E = $\frac{q}{4 π \in_{0} d^{2}}$ ,
where q is the charge and R the distance between the point and the charge.