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Question

A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge $$q_0$$ at this point and measure F/$$q_0$$ on this charge. Then, 


A
E>F/q0
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B
E<F/q0
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C
E=F/q0
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D
none of these
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Solution

The correct option is A $$ E > F / q_0$$
$$\displaystyle E = \frac{kQ}{r^2}$$

$$\displaystyle F = \frac{kQ q_0 }{r_1^2}     or      \frac{F}{q_0 } = \frac{kQ}{r_1^2}$$         (ii)

As $$r_1 > r$$, so from equation (i) and (ii), we get $$E > F/q_0$$

Physics
NCERT
Standard XII

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