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Question

A power of convex lens is + 4.0 D. At what distance should the object from the lens be placed to obtain its real and inverted image of the same size on the screen?
(Ans : u = 50 cm. At the centre of curvature of lens)


Solution

Given, power of the lens, $$ P = + 4D$$
we know that, focal length $$(f)  = \frac{1} {P} = 0.25 \space m$$
Given, size of the object = size of the image
For convex lens, this condition is possible only
When the object is placed at the centre of curvature.
$$\therefore$$ Object distance = $$2f = 2 \times 0.25 \space m = 0.5 \space m \space or \space 50 \space cm$$

Physics

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