Question

# A power of convex lens is + 4.0 D. At what distance should the object from the lens be placed to obtain its real and inverted image of the same size on the screen?(Ans : u = 50 cm. At the centre of curvature of lens)

Solution

## Given, power of the lens, $$P = + 4D$$we know that, focal length $$(f) = \frac{1} {P} = 0.25 \space m$$Given, size of the object = size of the imageFor convex lens, this condition is possible onlyWhen the object is placed at the centre of curvature.$$\therefore$$ Object distance = $$2f = 2 \times 0.25 \space m = 0.5 \space m \space or \space 50 \space cm$$Physics

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