CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A pressure of 1.5 pascal acts on a surface of area 13 square centimetres. The actual thrust acting on the surface is newton.

A
7.2×104
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11.3×104
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
19.5×104
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 19.5×104
Given: Area of contact, A=13 cm2=13×104 m2
Let the thrust be F.
Pressure acting on the surface, P=1.5 Pa=FA
1 Pa=1 Nm2
1.5 Pa=F13×104
F=1.5 Nm2×13×104 m2
F=19.5×104 N

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Buoyancy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon