Question

# A projectile is fired at an angle of 45o with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is

A
tan1(32)
B
45o
C
60o
D
tan112

Solution

## The correct option is A tan−112Let α be the elevation angle ⇒ tanα=HR/2 But when we take the ratio of maximum height with range of projectile we get, HR=tan θ4 ⇒tan α=2tan 45o4 or α=tan−1(12)

Suggest corrections