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Question

A projectile is fired at an angle of 45o with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is


Your Answer
A
tan1(32)
Your Answer
B
45o
Your Answer
C
60o
Correct Answer
D
tan112

Solution

The correct option is A tan112
Let α be the elevation angle
tanα=HR/2
But when we take the ratio of maximum height with range of projectile we get,
HR=tan θ4
tan α=2tan 45o4
or α=tan1(12)

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