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Question

A projectile is fired from the surface of the earth with a velocity of 5 ms1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 ms1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet (in ms2) is

(Given g=9.8 ms2)

A
3.5
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B
5.9
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C
16.3
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D
110.8
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Solution

The correct option is A 3.5
If both the trajectories are identical, then
He=Hp (H is the maximum height of a projectile)
52sin2θ2ge=32sin2θ2gp (θ is same in both the case)
gp=925ge
=925×9.8=3.52 m/s2
Hence, the correct answer is option (A).


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